Solving Inequalities with Logarithms and Exponents
1.
Let's start by seeing which x can even be put into the
logarithm function in the
inequality. Since the domain of a logarithm function is (0,∞), we need
We know the fraction will be positive when both the
numerator and denominator are
the same sign. To see when each piece changes sign, we look for when each piece
is
0. The numerator: The denominator:
We now divide up the real line into intervals divided by these numbers x = 1/2,
2, and
check the sign of the numerator and denominator in each interval.
Interval

So the domain of is
. Note we do not include the end
points (why?).
Now lets go on to solve the inequality. We first exponentiate both sides with
base 2
(since this is the inverse operation of logarithm base 2).
The next step in isolating x is to multiply by both sides
by x  2. Since multiplying
by a negative number reverses an inequality, we need to be careful about the
sign
of x  2, since that will affect the direction of the inequality. Let's first say
x > 2, so x  2 > 0 and the direction of the inequality doesn't change, and we
get
Well this violates our assumption that x > 2, so this
tells us (2,∞) is not part of
our solution set. Next say x < 2, so x2 is negative, and when we multiply by
this
we need to switch the sign of the inequality:
So we have that x > 1 and our assumption here was x < 2,
giving us x is in
(1, 2). But now we need to go back and check the domain of the logarithm
function,
and see if any values in (1, 2) are not in the domain. The domain we found is
, so we see that [1/2, 2) needs to be removed from (1, 2), leaving
only (1, 1/2).
To illustrate this point, take x = 1. This satisfies the inequality
, but 1 is not
in the domain of our original logarithm function and cannot be put into our
original
inequality.
So the final answer  the solution set to the inequality is (1, 1/2), or 1 < x
< 1/2.
2.
Again we'll first check the domain. ln x gives us the domain restriction x > 0,
and
ln(x4) gives us the domain restriction x > 4. Since a number > 4 is > 0, our
domain
is x > 4.
Now we'll solve the inequality, first using properties of logs and then
exponentiating
both side (with base e):
The product (x  7)(x + 3) will be less than 0 when the
factors have opposite sign.
You can set up a similar table as in the first problem, and we see that the
factors are
opposite sign when 3 < x < 7. Now since the inequality is ≤, not a strict <, we
include the endpoints 3 and 7 (since the left side is allowed to actually =
0).
Now checking the domain, we found x > 4, so the actual solution set reduces from
[3, 7] to (4, 7]. Notice 4 is not included, since it is not in the domain of
ln(x  4).
So the final answer  the solution set to the inequality is (4, 7], or 4 < x ≤7.